A copper ball of mass `m = 1 kg` with a radius of `r = 10 cm` rotates with angular velocity `omega = 2 rad//s` about an axis passing through its centre. The work should be performed to increase the angular velocity of rotation of the ball two fold is.

Explanation

To solve the problem, we need to calculate the work done to increase the angular velocity of a copper ball from an initial angular velocity to a final angular velocity that is double the initial value. We will follow these steps:

### Step 1: Calculate the Moment of Inertia (I) of the Copper Ball
The moment of inertia \( I \) for a solid sphere is given by the formula:
\[ I = \frac{2}{5} m r^2 \]
where \( m = 1 \, \text{kg} \) and \( r = 0.1 \, \text{m} \) (since 10 cm = 0.1 m).
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