A uniform flag pole of length L and mass...

A uniform flag pole of length `L `and mass `M` in pivoted on the ground with a frictionless hinge. The flag pole makes an angle `theta` with the horizontal. The moment of inertia of the flag pole about one end is `(1//3) ML^(2)`. If starts falling from the position shown in figure, the linear acceleration of the free end of the flag pole-labeled `P` - would be.
.

`(2/3)gcostheta`

`(2/3)g`

`g`

`(3/2)gcostheta`

Text Solution

Verified by Experts

The correct Answer is:

`(MgL)/2costheta=(ML^(2))/3alpha`
`alpha=3/2(gcostheta)/L`
`a=alphaL=3/2gcostheta`

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