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Two points of a rod move with velocity 3...

Two points of a rod move with velocity `3 v` and `v` perpendicular to the rod and in the same direction. Separated by a distance `r`. Then the angular velocity of the rod is :

A

`(3v)/r`

B

`(4r)/r`

C

`(5v)/r`

D

`(2v)/r`

Text Solution

Verified by Experts

The correct Answer is:
D
`omega_(rod)=(v_(rel))_(_|_)/r`
`(V_(rel))_(_|_)` is the velocity of one point w.r.t other perpendicular to rod.
`omega_(rod)=(3v-v)/r` and `r` being the distance between the points `omega_(rod)=(2v)/r`
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