A force `F` acts tangentially at the highest point of a disc of mass `m` kept on a rough horizontal plane. If the disc rolls without slipping, the acceleration of centre of the disc is:

Options

A. `(2F)/(3m)`
B. `(10F)/(7m)`
C. zero
D. `(4F)/(3m)`

Answer

D

Explanation

`F+f=Ma` ………..i
`FR=fR=(MR^(2))/2 a/R`……ii
`F-f=(Ma)/w`………..iii
`2F=(2Ma)/wimpliesa=(4F)/(3M)`