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Two point masses of 0.3 kg and 0.7kg are...

Two point masses of 0.3 kg and 0.7kg are fixed at the ends of a rod of length 1.4 m and of negligible mass. The rod is set rotating about an axis perpendicular to its length with a uniform angular speed. The point on the rod through which the axis should pass in order that the work required for rotation of the rod is minimum, is located at a distance of

A

`0.42 m` from the mass of `0.3 kg`

B

`0.70 m` from the mass of `0.7 kg`

C

`0.98 m` from the mass of `0.3 kg`

D

`0.98 m` from the mass of `0.7 kg`

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To solve the problem of finding the point on the rod through which the axis should pass to minimize the work required for rotation, we will follow these steps: ### Step 1: Understand the System We have two point masses, \( m_1 = 0.3 \, \text{kg} \) and \( m_2 = 0.7 \, \text{kg} \), fixed at the ends of a rod of length \( L = 1.4 \, \text{m} \). The goal is to find the position along the rod where the axis of rotation should be placed to minimize the work done for rotation. ### Step 2: Define the Center of Mass The center of mass (CM) of a system of point masses can be calculated using the formula: \[ x_{cm} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2} \] where \( x_1 \) and \( x_2 \) are the positions of the masses. We can set \( x_1 = 0 \) (position of \( m_1 \)) and \( x_2 = 1.4 \, \text{m} \) (position of \( m_2 \)). ### Step 3: Substitute the Values Substituting the values into the center of mass formula: \[ x_{cm} = \frac{(0.3 \, \text{kg} \cdot 0) + (0.7 \, \text{kg} \cdot 1.4 \, \text{m})}{0.3 \, \text{kg} + 0.7 \, \text{kg}} \] \[ x_{cm} = \frac{0 + 0.98 \, \text{kg m}}{1.0 \, \text{kg}} = 0.98 \, \text{m} \] ### Step 4: Interpret the Result The center of mass is located at a distance of \( 0.98 \, \text{m} \) from the \( 0.3 \, \text{kg} \) mass. This is the point on the rod through which the axis of rotation should pass to minimize the work required for rotation. ### Step 5: Conclusion Thus, the point on the rod through which the axis should pass is located at a distance of \( 0.98 \, \text{m} \) from the \( 0.3 \, \text{kg} \) mass. ---

To solve the problem of finding the point on the rod through which the axis should pass to minimize the work required for rotation, we will follow these steps: ### Step 1: Understand the System We have two point masses, \( m_1 = 0.3 \, \text{kg} \) and \( m_2 = 0.7 \, \text{kg} \), fixed at the ends of a rod of length \( L = 1.4 \, \text{m} \). The goal is to find the position along the rod where the axis of rotation should be placed to minimize the work done for rotation. ### Step 2: Define the Center of Mass The center of mass (CM) of a system of point masses can be calculated using the formula: \[ ...
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