Home
Class 11
PHYSICS
When a bicycle is in motion, the force o...

When a bicycle is in motion, the force of friction exerted by the ground on the two wheels is such that it acts

A

in the backward direction on the front wheel and in the forward direction on the rear wheel

B

in the forward direction on the front wheel and in the backward direction on the rear wheel

C

in the backward direction on both the front and the rear wheels

D

in the forward direction on both the front and the rear wheels

Text Solution

Verified by Experts

The correct Answer is:
C

When the cycle is not pedaled but it is in motion (due to previous effort) the wheels move in the direction such that the centre of mass of the wheels moves forward. Rolling friction will act in the opposite direction to the relative motion of the centre of mass of the body with respect to the ground.
Therefore the rolling friction will act in the backward directioin in both the wheels. The sliding friction will act in the forward direction of the rear wheel during pedaling.
Promotional Banner

Topper's Solved these Questions

  • RIGID BODY DYNAMICS 2

    CENGAGE PHYSICS ENGLISH|Exercise AR_TYPE|2 Videos
  • RIGID BODY DYNAMICS 2

    CENGAGE PHYSICS ENGLISH|Exercise LC_TYPE|8 Videos
  • RIGID BODY DYNAMICS 2

    CENGAGE PHYSICS ENGLISH|Exercise SCQ_TYPE|29 Videos
  • RIGID BODY DYNAMICS 1

    CENGAGE PHYSICS ENGLISH|Exercise Integer|11 Videos
  • SOUND WAVES AND DOPPLER EFFECT

    CENGAGE PHYSICS ENGLISH|Exercise Integer|16 Videos

Similar Questions

Explore conceptually related problems

(A) : When a bicycle is in motion, the force of friction exerted by the ground on the two wheels is always in forward direction. (R ) : The frictional force only when the bodies are in contact.

Find the force of friction acting between both the blocks shown in the figure.

A roller of mass 500kg is attached by a light horizontal chain to a tractor of mass 500kg. Assume the force of friction exerted by the ground to be 1000N. If the system has a forward acceleration of 2ms^(-2) , calculate (i) the total force required for the motion and (ii) the tension in the chain.

A bicycle has pedal rods of length 16 cm connected to sprocketed disc of radius 10 cm . The bicycle wheels are 70 cm in diameter and the chain runs over a gear of radius 4cm . The speed of the cycle is constant and the cyclist applies 100 N for, that is always perpendicular to the pedal rod, as shown in figure. Assume tension in the lower part of chain is negligible. The cyclist is peddling at a constant rate of two revolutions per second. Assume that the force applied by other foot is zero when one foot is exerting 100 N force. Neglect friction within cycle parts and the rolling friction. The net force of the friction on the rear wheel due to the road is:

"When a person walks on a rough surface the frictional force exerted by the surface on the person is opposite to the direction of his motion". Is it true or false ?

Assertion : Angle of repose is equal to angle of limiting friction. Reason : When the body is just at the point of motion, the force of friction in this stage is called as limiting friction.

A spring is compressed between two toy carts to masses m_1 and m_2 . When the toy carts are released, the spring exerts on each toy cart equal and opposite forces for the same small time t. If the coefficients of friction mu between the ground and the toy carts are equal, then the magnitude of displacements of the toy carts are in the ratio

When a person walks on a rough surface, the frictional force exerted by surface on the person is opposite to the direction of his motion. It is the force exerted by the road on the person that causes the motion.

A car weighs 1800 kg . The distance between its front and back axles is 1.8 m . Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front wheel and each back wheel.