What fraction of an iceberg ice beneath the surface of the sea? Density of sea water `(rho)=1.028xx10^(3)kg//m^(3)`, density of ice d. `=0.917xx10^(3)kg//m^(3)`
Text Solution
AI Generated Solution
To solve the problem of determining what fraction of an iceberg is submerged beneath the surface of the sea, we can use Archimedes' principle. Here’s a step-by-step solution:
### Step 1: Understand the Problem
We need to find the fraction of the iceberg that is submerged in the sea. We know the densities of sea water and ice.
### Step 2: Identify Given Data
- Density of sea water, \( \rho_{water} = 1.028 \times 10^3 \, \text{kg/m}^3 \)
- Density of ice, \( \rho_{ice} = 0.917 \times 10^3 \, \text{kg/m}^3 \)
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An iceberg floats on fresh water with a part of it outside the water surface. Calculate the fraction of the volume of the iceberg which is below the water surface. Given : density of ice =917kgm^(-3) , density of fresh water =1000kgm^(-3)
A piece of alloy of gold and silver weighs 2 kg in air and 1.86 kg in water. What is the mass of silver? Density of gold is 19.3 xx 10^(3) kgm^(-3) . Density of silver is 10.5 xx 10^(3) kg m^(-3)
Water rises up in a glass capillary upto a heigh 10 cm, while mercury falls down by 3.5 cm in the same capillary. If the angles of contact for water-glass and mercury-glass are taken as 0^(@) and 135^(@) respectively, compare the surface tensions of water and mercury. [Given density of water = 10^(3) kg m^(-3) , density of mercury = 13.6 xx 10^(3) kg m^(-3) ]
If the density of ice is 0.9gcm^(-3) , what portion of an iceberg will remain below the surface of water in a sea? (Density of sea water =1.1gcm^(-3) )
An ice berg floats on fresh water with a part of it outside the water surface. Calculate the fraction of the volume of the ice berg which is below the water surface. (Density of ice = 917 "kgm"^(-3) , Density of water = 1000 "kgm"^(-3) )
A tank contains water and mercury as shown in figure. An iron cube of edge d=6 cm is in equilibrium as shown. (density of iron =7.8xx10^(3) kg//m^(3) , density of mercury =13.6xx10^(3) kg//m^(3) , density of water =10^(3) kgm^(3) )(Neglect the atmospheric pressure) Time period of small oscillations of block is
Two metal spheres are falling through a liquid of density 2xx10^(3)kg//m^(3) with the same uniform speed. The material density of sphere 1 and sphere 2 are 8xx10^(3)kg//m^(3) and 11xx10^(3)kg//m^(3) respectively. The ratio of their radii is :-
A metallic sphere of radius 1.0 xx 10^(-3) m and density 1.0 xx 10^(4) kg//m^(3) enters a tank of water, after a free fall through a distance of h in the earth's gravitational field. If its velocity remains unchanged after entering water, determine the value of h . Given: coefficient of viscosity of water = 1.0 xx 10^(-3) N s//m^(2), g = 10ms^(-12) and density of water = 1.0 xx 10^(3) kg//m^(3) .
In two identical communicating vessel we poured water (see picture). In one of them we put an ice ball of volume V=100 cm^(3) which gets exactly half immersed in the water. The density of water rho_(w)=1000kg//m^(3) the density of ice rho_(i)=900kg//m^(3) Select the correct statement (s). Soon after placing the ice ball in left vessel.
What is the terminal velocity of a copper ball of radius 2.0 mm, which falls through an oil tank? Given that density of oil = 1.5 xx 10^(3) kg m^(-3) , density of copper = 8.9 xx 10^(3) kg m^(-3) and viscosity of oil is 0.99 kg m^(-1)s^(-1) .
