A ball floats on the surface of water in a container exposed to the atmosphere. Will the ball remain immersed at its initial depth or will it sink or rise somewhat if the container is shifted to the moon?

Explanation

To solve the problem of whether a ball floating on the surface of water in a container will remain at its initial depth, sink, or rise when the container is shifted to the moon, we can follow these steps:

### Step 1: Understand the Forces Acting on the Ball
When the ball is floating on the surface of the water, it experiences two main forces:
- The **weight of the ball (W)** acting downwards, which is given by \( W = \rho_{ball} \cdot V \cdot g \), where \( \rho_{ball} \) is the density of the ball, \( V \) is the volume of the ball, and \( g \) is the acceleration due to gravity.
- The **buoyant force (F_b)** acting upwards, which is equal to the weight of the water displaced by the submerged part of the ball. This is given by \( F_b = \rho_{water} \cdot V_s \cdot g \), where \( V_s \) is the submerged volume of the ball.

### Step 2: Analyze the Situation on Earth
...