A gardener holds a pipe of inside cross-sectional area `3.60 cm^(2)` at a height of `1.50 m` from ground. The opening at the nozzle of pipe has cross-sectional area `0.250 cm^(2)`. Water velocity in the segment of the hose that lies on the ground is `50.0 cm//s`. a. What is the velocity of water leaving the nozzle? b. What is the thrust force experienced by the gardener due to flow of water through nozzle. c. What is the water pressure in the hose on the ground?

Explanation

To solve the problem step by step, we will address each part of the question systematically.

### Given Data:
- Cross-sectional area of the pipe, \( A_1 = 3.60 \, \text{cm}^2 = 3.60 \times 10^{-4} \, \text{m}^2 \)
- Cross-sectional area of the nozzle, \( A_2 = 0.250 \, \text{cm}^2 = 0.250 \times 10^{-4} \, \text{m}^2 \)
- Velocity of water in the hose on the ground, \( V_1 = 50.0 \, \text{cm/s} = 0.50 \, \text{m/s} \)
- Height of the nozzle from the ground, \( h = 1.50 \, \text{m} \)
- Density of water, \( \rho = 1000 \, \text{kg/m}^3 \)
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