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In the figure, the cross-sectional area ...

In the figure, the cross-sectional area of the smaller tube is a and that of the larger tube is `2a`. A block of mass `m` is kept in the smaller tube having the base area that of the tube. The difference between water levels of the two tubes is

A

`(P_(0))/(rhog)+m/(arho)`

B

`(P_(0))/(rhog)+m/(2arho)`

C

`m/(arho)`

D

`m/(2rhoa)`

Text Solution

Verified by Experts

The correct Answer is:
C
Pressure at the bottom level of the block
`P=(mg)/a+P_(0)`…..i
The pressure at the same level remains the same.
Hence `(mg)/a+P_(0)=hrhog+P_(0)impliesm/(arho)`
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