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There are two identical small holes of a...

There are two identical small holes of area of cross section a on the opposite sides of a tank containing liquid of density `rho`. The differences in height between the holes is `h`. The tank is resting ona smooth horizontal surface. The horizontal force which will have to be applied on the tank to keep it inequilibrium is

A

`ghrhoa`

B

`(2gh)/(rhoa)`

C

`2rhoagh`

D

`(rhogh)/a`

Text Solution

Verified by Experts

The correct Answer is:
C
Thrust force `F=F_(1)-F_(2)=rhoav_(1)^(2)-rhoav_(2)^(2)`
`=rhoa(2gh_(1))-rhoa(2gh_(2))`
`=2rhoag(h_(1)-h_(2))=2rhoagh`
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