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In the figures shown an ideal liquid is ...

In the figures shown an ideal liquid is flowing through the tube which is of uniform area of cross-section . The liquid has velocities `v_(A) and v_(B)`, and pressures `P_(A) and P_(B)` at point A and B respectively. Then

A

`v_(A)=v_(B)`

B

`v_(A)gtv_(B)`

C

`P_(A)=P_(B)`

D

`P_(B)gtP_(A)`

Text Solution

Verified by Experts

The correct Answer is:
A, D
As per the continuity equation `Av=`constant `v_(A)=v_(B).` As point `B` is at the lower level, hence `p_(B)gtp_(A)`.
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