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A thin uniform cylindrical shell, closed...

A thin uniform cylindrical shell, closed at both ends, is partially filled with water. It is floating vertically in water in half-submerged state. If `rho_c` is the relative density of the material of the shell with respect to water, then the correct statement is that the shell is

A

More than half-filled if `rho_(c)`, is less than `0.5 `

B

more than half-filled `rho_(c)` is more than `1.0 c`,

C

half filled if `rho_(c)` is more than `0.5`

D

less than half-filled if `rho_(c)` is less than `0.5`

Text Solution

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The correct Answer is:
To solve the problem of a thin uniform cylindrical shell that is partially filled with water and floating vertically in a half-submerged state, we will analyze the forces acting on the shell and the relationship between the densities involved. ### Step-by-Step Solution: 1. **Understanding the System**: - We have a cylindrical shell that is closed at both ends and is floating in water. It is partially filled with water and is in a vertical position, half-submerged. - Let \( V_s \) be the volume of the shell, \( V_w \) the volume of water inside the shell, and \( V_a \) the volume of air inside the shell. 2. **Weight of the Shell**: - The weight of the shell can be expressed as: \[ W_{\text{shell}} = V_s \cdot \rho_c \cdot g \] - Here, \( \rho_c \) is the density of the shell material, and \( g \) is the acceleration due to gravity. 3. **Buoyant Force**: - The buoyant force acting on the shell is equal to the weight of the water displaced by the submerged part of the shell: \[ F_b = (V_w + V_a) \cdot \rho_w \cdot g \] - Here, \( \rho_w \) is the density of water. 4. **Equilibrium Condition**: - For the shell to float in equilibrium, the weight of the shell must equal the buoyant force: \[ W_{\text{shell}} = F_b \] - Substituting the expressions for weight and buoyant force, we have: \[ V_s \cdot \rho_c \cdot g = (V_w + V_a) \cdot \rho_w \cdot g \] 5. **Simplifying the Equation**: - Canceling \( g \) from both sides, we get: \[ V_s \cdot \rho_c = (V_w + V_a) \cdot \rho_w \] 6. **Volume Relationships**: - Since the shell is half-submerged, we can express the volumes as: \[ V_w + V_a = V_s \] - This implies that the total volume of the shell is equal to the sum of the volumes of water and air. 7. **Analyzing Relative Density**: - The relative density \( \rho_c \) is defined as the ratio of the density of the shell material to the density of water: \[ \rho_c = \frac{\text{Density of shell}}{\text{Density of water}} \] - If \( \rho_c < 0.5 \), it indicates that the shell is less dense than half the density of water, meaning it is more buoyant and thus more than half-filled with water. 8. **Conclusion**: - Therefore, if \( \rho_c < 0.5 \), the shell is more than half-filled with water. If \( \rho_c > 0.5 \), it would be less than half-filled. - The correct statement is that the shell is more than half-filled if \( \rho_c < 0.5 \). ### Final Answer: The shell is more than half-filled if \( \rho_c < 0.5 \).

To solve the problem of a thin uniform cylindrical shell that is partially filled with water and floating vertically in a half-submerged state, we will analyze the forces acting on the shell and the relationship between the densities involved. ### Step-by-Step Solution: 1. **Understanding the System**: - We have a cylindrical shell that is closed at both ends and is floating in water. It is partially filled with water and is in a vertical position, half-submerged. - Let \( V_s \) be the volume of the shell, \( V_w \) the volume of water inside the shell, and \( V_a \) the volume of air inside the shell. ...
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