Compressibility of water is `5xx10^(-10)m^(2)//N`. Find the decrease in volume of `100 mL` of water when subjected to a pressure of `15 MPa`.

Explanation

To solve the problem, we need to calculate the decrease in volume of water when subjected to a specific pressure using the given compressibility. Here's the step-by-step solution:

### Step 1: Understand the given values
- Compressibility of water, \( K = 5 \times 10^{-10} \, \text{m}^2/\text{N} \)
- Initial volume of water, \( V_0 = 100 \, \text{mL} = 100 \times 10^{-6} \, \text{m}^3 \) (since \( 1 \, \text{mL} = 10^{-6} \, \text{m}^3 \))
- Pressure applied, \( P = 15 \, \text{MPa} = 15 \times 10^6 \, \text{N/m}^2 \)

### Step 2: Use the formula for change in volume
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