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A catapult consists of two parallel rubb...

A catapult consists of two parallel rubber strings each of lengths, `10 cm` and cross sectional area `10mm^(2)`. When stretched by `5 cm`, it can throw a stone of mass `10 gm` to a vertical height of `25 m`. Determine Young's modulus of elasticity of rubber.

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To determine the Young's modulus of elasticity of rubber in the given catapult scenario, we can follow these steps: ### Step 1: Understand the Given Data - Length of each rubber string, \( L = 10 \, \text{cm} = 0.1 \, \text{m} \) - Cross-sectional area of each rubber string, \( A = 10 \, \text{mm}^2 = 10 \times 10^{-6} \, \text{m}^2 \) - Stretch of the rubber strings, \( \Delta L = 5 \, \text{cm} = 0.05 \, \text{m} \) - Mass of the stone, \( m = 10 \, \text{g} = 10 \times 10^{-3} \, \text{kg} \) - Height to which the stone is thrown, \( h = 25 \, \text{m} \) ...
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