A powder comprising particle of various sizes is stirred up in a vessel filled to a height of `10 cm` with water. Assuming the particle to be spherical, find the size of the largest particle that will remain in suspension after `1h` (density of powder `=4g//cm^(3)`, viscosity of water `=0.01`poise).

Explanation

To solve the problem of finding the size of the largest particle that will remain in suspension after 1 hour in water, we can follow these steps:

### Step 1: Identify the given data
- Height of water in the vessel, \( h = 10 \, \text{cm} = 0.1 \, \text{m} \)
- Density of the powder, \( \rho_p = 4 \, \text{g/cm}^3 = 4000 \, \text{kg/m}^3 \)
- Density of water, \( \rho_w = 1 \, \text{g/cm}^3 = 1000 \, \text{kg/m}^3 \)
- Viscosity of water, \( \mu = 0.01 \, \text{poise} = 0.001 \, \text{N s/m}^2 \)
- Time, \( t = 1 \, \text{hour} = 3600 \, \text{s} \)
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