A rubber cube of side `5 cm` has one side fixed while a tangential force equal to `1800 N` is applied to opposite face. Find the shearing strain and the lateral displacement of the strained face. Modulus of rigidity for rubber is `2.4 xx 10^(6) N//m^(2)`.

Explanation

To solve the problem, we need to find the shearing strain and the lateral displacement of a rubber cube when a tangential force is applied. Here are the steps to arrive at the solution:

### Step 1: Identify the given data
- Side length of the rubber cube, \( L = 5 \, \text{cm} = 0.05 \, \text{m} \)
- Tangential force, \( F = 1800 \, \text{N} \)
- Modulus of rigidity for rubber, \( G = 2.4 \times 10^6 \, \text{N/m}^2 \)

### Step 2: Calculate the area of the face of the cube
...