Home
Class 11
PHYSICS
A cubical block (of side 2 m) of mass 20...

A cubical block (of side `2 m`) of mass `20 kg` slides on inclined plane lubricated with the oil of viscosity `eta=10^(-1)` with constant velocity of `10 ms^(-1)`. Find out the thickness of the layer of liquid (take `g = 10 ms^(-2)`).

Text Solution

Verified by Experts

`F=F'=etaA(dv)/(dy)mgsintheta` `[ (dv)/(dy)=v/h]`
`20xx10xxsin30^@=etaxx4xx10/h`

`h=(40xx10^(-2))/100 [eta=10^(-1)poise=10^(-2)Ns//m^(2)]`
`=4xx10^(-3)m=4mm`
Promotional Banner

Topper's Solved these Questions

  • PROPERTIES OF SOLIDS AND FLUIDS

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 5.3|9 Videos

  • PROPERTIES OF SOLIDS AND FLUIDS

    CENGAGE PHYSICS ENGLISH|Exercise Subjective|16 Videos

  • PROPERTIES OF SOLIDS AND FLUIDS

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 5.1|12 Videos

  • NEWTON'S LAWS OF MOTION 2

    CENGAGE PHYSICS ENGLISH|Exercise Integer type|1 Videos

  • RIGID BODY DYNAMICS 1

    CENGAGE PHYSICS ENGLISH|Exercise Integer|11 Videos

Similar Questions

Explore conceptually related problems

A cubical block (of sie 2m) of mass 20 kg slides on inclined plane lubricated with the oil of viscosity eta=10^(-1) poise with constant velocity of 10 m/s find out the thickness of layer of liquid ( g=10m//s^(2) )

A wooden box of mass 8kg slides down an inclined plane of inclination 30^(@) to the horizontal with a constant acceleration of 0.4ms^(-2) What is the force of friction between the box and inclined plane ? (g = 10m//s^(2)) .

A wooden box of mass 8kg slides down an inclined plane of inclination 30^(@) to the horizontal with a constant acceleration of 0.4ms^(-2) What is the force of friction between the box and inclined plane ? (g = 10m//s^(2)) .

A sliding fit cylindrical body of mass of 1 kg drops vertically down at a constant velocity of 5cms^(-1) . Find the viscosity of the oil.

The de-Broglie wavelength associated with a particle of mass 10^-6 kg moving with a velocity of 10 ms^-1 , is

A block starts moving up a fixed inclined plane of inclination 60^(@)C with a velocityof 20 ms^(-1) and stops after 2s. The approximate value of the coefficient of friction is [g = 10 ms^(-2) ]

A gun fire bullets each of mass 1 g with velocity of 10 ms ^(-1) by exerting a constant force of 5 g weight. Then , the number of bullets fired per second is (take g = 10 ms ^(-2) )

If the force constant of spring is 50Nm^(-1) , find mass of the block, if it an rests in the given situation (g=10ms^(-2) ).

One of the rectangular components of a velocity of 20 ms^(-1) is 10 ms^(-1) . Find the other component.

If the elevator in shown figure is moving upwards with constant acceleration 1 ms^(-2) , tension in the string connected to block A of mass 6 kg would be ( take, g =10 ms^(-2) )