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A glass tube of circular cross section i...

A glass tube of circular cross section is closed at one end. This end is weighted and the tube floats vertically in water, heavy end down. How far below the water surface is the end of the tube? Given: outer radius of the tube is `0.14 cm`, mass of weighted tube is `0.2 g`, surface tension of water `73 dyn//cm` and `g = 980 cms^(-12)`.

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AI Generated Solution

To solve the problem, we need to analyze the forces acting on the glass tube and apply the principles of buoyancy and surface tension. Here’s a step-by-step solution: ### Step 1: Identify the forces acting on the tube The forces acting on the tube are: - The weight of the tube, \( W = mg \), acting downwards. - The upthrust (buoyant force), \( U \), acting upwards. - The surface tension force, \( T \), acting horizontally at the water surface. ...
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