Two wires of diameter `0.25 cm`, one made of steel and other made of brass, are loaded as shown in the figure. The unloaded length of the steel wire is `1.5 m` and that of brass is `1.0 m`. Young's modulus of steel is `2.0 xx 10^(11)`Pa and that of brass is `1.0 xx 10^(11)` Pa. Compute the ratio of elongations of steel and brass wires. `(/_\l_("steel"))/(/_\l_("brass"))=?`

Answer

`1.25`

Explanation

`/_\l_("brass")=(6gxx1.0)/(Axx1xx10^(11))`
`/_\l_("steel")=(10gxx1.5)/(Axx2xx10^(11))`
After solving equation we get `(/_\l_("steel"))/(/_\l_("brass"))=1.25`