Calculate the pressure indise a small air bubble of radius `0.01 mm` situated at a depth of `h=20 m` below the fre surface of liquid of density `rho_(1)=10^(3)kg//m^(3), rho_(2)=800km//m^(3)` and surface tension `T_(2)=7.5xx10^(-2)N//m.` The thickness of the first liqid is `h_(1)=15 m` and `h_(2)=25m`.

Answer

NA

Explanation

`P_(C)=P_(B)+(2T)/r`
`P_(B)=P_(L)A=rho_(1)gh_(1)+rho_(2)g(h-h_(1))`

where `P_(A)=P_(0)`
`P_(C)=P_(0)+rho_(1)gh_(1)+rho_(2)g(h-h_(1))+(2T)/r`
Then evaluate by putting the numerical values.