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Young's modulus of rubber is 10^(4) Nm^(...

Young's modulus of rubber is `10^(4) Nm^(-2)` and area of cross-sectionis `2 cm^(2)` . If force of `2xx10^(5)` dynes is applied along its length ,then its initial length L becomes

A

`3l`

B

`4l`

C

`2l`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C

`/_\l=(Fl)/(aY)`
`/_\l=(2xx10^(5)xx1)/(2xx10^(4)xx10^(4))` or `/_\l=1`
So, new length is `2l`.
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