When the load on a wire is increased from 3 kg wt to 5 kg wt the elongation increases from 0.61 mm to1.02 mm. The required work done during the given wire?

Options

A. `0.16J`
B. `0.016J`
C. `1.6J`
D. `16J`

Answer

B

Explanation

Work done `= 1/2xx` stretching `xx` extension.
Therefore, net work done in increasing the length from `0.164 mm` to `1.02 mm` is
`W_(2)-W_(1)=1/2x5xx9.8xx1.02xx10^(-3)-1/2`