A light wire AB of length 10 cm can slide on a vertical frame as shown in figure. There is a film of soap solution trapped between the frame and the wire. Find the load W that should be suspended from the wire to keep it in equilibrium. Neglect friction. Surface tension of soat solution `=25` dyne `cm^-1`. Take `g=10 ms^-2`

Options

A. `0.2g`
B. `0.3g`
C. `0.4g`
D. `0.5g`

Answer

D

Explanation

`25xx10^(-3)xx2xx0.1=mxx10`
or `m=(5xx10^(-3))/10 kg =0.5 g`