A drop of liquid of density `rho` is floating half-immersed in a liquid of density `d`. If `sigma` is the surface tension the diameter of the drop of the liquid is

Options

A. `(TA^(2))/V`
B. `(2TA^(2))/V`
C. `(4TA^(2))/V`
D. `(TA^(2))/(2V)`

Answer

B

Explanation

Pressure difference `=T/R=T/(t//2)=(2T)/t`
force `=(2T)/tA`
But `V=At ` or `t=V/A`
`:.` Force `=(2TA^(2))/V`