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Between a plate of area 100 cm^(2) and a...

Between a plate of area `100 cm^(2)` and another plate of area `100 m^(2)` there is a `1 mm`, thick layer of water, if the coefficient of viscosity of water is `0.01` poise, then the force required to move the smaller plate with a velocity `10 cms^(-1)` with reference to large plate is

A

`100 dyn`

B

`10^(4)dyn`

C

`10^(6) dyn`

D

`10^(9)dyn`

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The correct Answer is:
To solve the problem, we need to calculate the force required to move a smaller plate with a given velocity in a viscous fluid. We will use the formula for viscous force, which is given by: \[ F = \eta \cdot A \cdot \frac{dv}{dz} \] Where: - \( F \) is the viscous force, - \( \eta \) is the coefficient of viscosity, - \( A \) is the area of the plate, - \( \frac{dv}{dz} \) is the velocity gradient. ### Step 1: Convert all units to CGS - The area of the smaller plate is given as \( 100 \, cm^2 \). - The area of the larger plate is \( 100 \, m^2 \) which we convert to \( cm^2 \): \[ 100 \, m^2 = 100 \times 10^4 \, cm^2 = 10^6 \, cm^2 \] - The thickness of the water layer is \( 1 \, mm \) which we convert to centimeters: \[ 1 \, mm = 0.1 \, cm \] - The coefficient of viscosity \( \eta \) is given as \( 0.01 \, poise \) (1 poise = 1 g/cm·s, so \( 0.01 \, poise = 0.01 \, g/cm·s \)). - The velocity \( v \) is given as \( 10 \, cm/s \). ### Step 2: Calculate the velocity gradient \( \frac{dv}{dz} \) - The velocity gradient \( \frac{dv}{dz} \) is calculated as: \[ \frac{dv}{dz} = \frac{10 \, cm/s - 0 \, cm/s}{0.1 \, cm} = \frac{10 \, cm/s}{0.1 \, cm} = 100 \, s^{-1} \] ### Step 3: Substitute values into the viscous force formula Now we substitute the values into the viscous force formula: - \( \eta = 0.01 \, g/cm·s \) - \( A = 100 \, cm^2 \) - \( \frac{dv}{dz} = 100 \, s^{-1} \) \[ F = 0.01 \, g/cm·s \cdot 100 \, cm^2 \cdot 100 \, s^{-1} \] ### Step 4: Calculate the force Calculating the force: \[ F = 0.01 \cdot 100 \cdot 100 = 100 \, g \cdot cm/s^2 \] Since \( 1 \, g \cdot cm/s^2 = 1 \, dyne \): \[ F = 100 \, dyne \] ### Final Answer The force required to move the smaller plate with a velocity of \( 10 \, cm/s \) is \( 100 \, dyne \). ---

To solve the problem, we need to calculate the force required to move a smaller plate with a given velocity in a viscous fluid. We will use the formula for viscous force, which is given by: \[ F = \eta \cdot A \cdot \frac{dv}{dz} \] Where: - \( F \) is the viscous force, - \( \eta \) is the coefficient of viscosity, - \( A \) is the area of the plate, ...
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