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Which of the following are correct?...

Which of the following are correct?

A

The product of bulk' modulus of elasticity and compressibility is `1`

B

A rope `1 cm` in diameter breaks if the tension in it exceeds `500 N`. The maximum tension that may be given to a similar rope of diameter `2 cm` is `2000 N`.

C

Both (a) and (b) are correct.

D

Neither (a) nor (b) is correct.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to evaluate the correctness of the given options based on the principles of physics related to elasticity and stress. ### Step-by-Step Solution: **Step 1: Evaluate Option A** - **Statement**: The product of bulk modulus of elasticity and compressibility is 1. - **Explanation**: - Bulk modulus (K) is defined as the measure of a substance's resistance to uniform compression. - Compressibility (β) is the measure of the relative volume change of a material in response to a pressure change, and it is the inverse of bulk modulus. - Mathematically, we have: \[ \beta = \frac{1}{K} \] - Therefore, the product of bulk modulus and compressibility is: \[ K \cdot \beta = K \cdot \frac{1}{K} = 1 \] - **Conclusion**: Option A is correct. **Step 2: Evaluate Option B** - **Statement**: A rope of 1 cm in diameter breaks if the tension in it exceeds 500 Newton. The maximum tension that may be given to a similar rope of diameter 2 cm is 2000 N. - **Explanation**: - The maximum stress (σ_max) in the rope can be calculated using the formula: \[ \sigma_{\text{max}} = \frac{F}{A} \] where \( F \) is the force (tension) and \( A \) is the cross-sectional area of the rope. - For a rope of diameter 1 cm: \[ A_1 = \frac{\pi}{4} d^2 = \frac{\pi}{4} (1 \text{ cm})^2 = \frac{\pi}{4} \text{ cm}^2 \] \[ \sigma_{\text{max}} = \frac{500 \text{ N}}{\frac{\pi}{4} \text{ cm}^2} = \frac{2000}{\pi} \text{ N/cm}^2 \] - For a rope of diameter 2 cm: \[ A_2 = \frac{\pi}{4} (2 \text{ cm})^2 = \frac{\pi}{4} \cdot 4 \text{ cm}^2 = \pi \text{ cm}^2 \] - Let the maximum tension for the 2 cm rope be \( x \): \[ \sigma_{\text{max}} = \frac{x}{\pi \text{ cm}^2} \] - Equating the maximum stress from both cases: \[ \frac{2000}{\pi} = \frac{x}{\pi} \] - Cancelling \( \pi \) from both sides, we find: \[ x = 2000 \text{ N} \] - **Conclusion**: Option B is correct. **Step 3: Evaluate Option C** - **Statement**: Both A and B are correct. - **Conclusion**: Since both options A and B have been verified to be correct, option C is also correct. ### Final Answer: - **Correct Options**: A, B, and C are all correct.

To solve the question, we need to evaluate the correctness of the given options based on the principles of physics related to elasticity and stress. ### Step-by-Step Solution: **Step 1: Evaluate Option A** - **Statement**: The product of bulk modulus of elasticity and compressibility is 1. - **Explanation**: - Bulk modulus (K) is defined as the measure of a substance's resistance to uniform compression. ...
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