Calculate the percentage decrease in the weight of a body when taken 32 km below the surface of the earth. Radius of the earth is 6400 km and g `= 9.8 ms^(-2)`
A
0.6%
B
0.2%
C
0.5%
D
0.7%
Text Solution
Verified by Experts
The correct Answer is:
C
Here , `d=32 km, R=6400 km` Weight of body at depth `d` is `=mg'=mg(1-d/R)` `%` decrease in weight `=(mg-mg')/(mg)` `=d/Rxx100=32/6400xx100=0.5%`
Find the percentage decrease in the weight of a body when taken 16 km below the surface of the earth. Take radius of the earth is 6400 km.
Determine the decrease in the weight of a body when it is taken 32 km below the earth surface. Take radius of the earth as 6400 km.
Find out the capacitance of the earth ? (Radius of the earth = 6400 km)
Find the depth at which the value of g becomes 25% of that at the surface of the earth. (Radius of the earth = 6400 km)
Calculate the height at which a man's weight becomes ( 4//9) of his weight on the surface of the earth, if the radius of the earth is 6400km.
What is the decrease in weight of a body of mass 800 kg when it is taken into a mine of depth 1500m? Radius of the earth is 6371km.
A satellite circled around the earth at a distance of 100 km. Determine its orbital velocity, if the radius of the earth is 6400 km and g = 9.8 ms^(-2) .
Calculate the mass of the earth from the following data. Radius of the earth, 6371km, g = 9.8 ms^(-2)
Find the value of 'g(i)' at a height of 100 km (ii) at height 6400 km from the surface of the earth. (Radius of the earth = 6400 km, g on the surface of the earth = 9.8 ms^(-2) .
If the value of g at the surface of the earth is 9.8 m//sec^(2) , then the value of g at a place 480 km above the surface of the earth will be (Radius of the earth is 6400 km)
