On a planet whose size is the same and mass four times as that of our earth, find the amount of work done to lift `3 kg` mass vertically upwards through `3 m` distance on the planet. The value of `g` on the surface of earth is `10 ms^(-2)`
Text Solution
AI Generated Solution
To solve the problem, we will follow these steps:
### Step 1: Determine the acceleration due to gravity on the new planet.
We know that the acceleration due to gravity (g) is given by the formula:
\[ g = \frac{G \cdot M}{R^2} \]
where:
- \( G \) is the gravitational constant,
- \( M \) is the mass of the planet,
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Ravi can throw a ball at a speed on the earth which can cross a river of width 10 m . Ravi reaches on an imaginary planet whose mean density is twice that of the earth. Find out the maximum possible radius of the planet so that if Ravi throws the ball at the same speed it may escape from the planet. Given radius of the earth = 6.4 xx 10^(6) m .
The mass of a planet and its diameter are three times those of earth's. Then the acceleration due to gravity on the surface of the planet is : (g =9.8 ms^(-2))
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A particle is fired vertically upwards from the surface of earth and reaches a height 6400 km. Find the initial velocity of the particle if R = 6400 km and g at the surface of earth is 10 m//s^(2) .
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Gravitational acceleration on the surface of a planet is (sqrt6)/(11)g. where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is (2)/(3) times that of the earth. If the escape speed on the surface of the earht is taken to be 11 kms^(-1) the escape speed on the surface of the planet in kms^(-1) will be
What should be the radius of a planet with mass equal to that of earth and escape velocity on its surface is equal to the velocity of light. Given that mass of earth is M=6xx10^(24)kg .
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If M be the mass of the earth, R its radius (assumed spherical) and G gravitational constant, then the amount of work that must be done on a body of mass m, so that it completely escapes from the gravity of the earth of the earth is given by
