A body is released at a distance far away from the surface of the earth. Calculate its speed when it is near the surface of earth. Given `g = 9.8 m s^(-2)`, radius of earth `R = 6.37 xx 10^(6) m`
Text Solution
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Conservation of energy implies `0+0=1/2mv^(2)-(GMm)/R` `v=sqrt((2GM)/R)=sqrt((2(R^(2)g))/R)` `=sqrt(2Rg)~~11.2xx10^(3)ms^(-1)`
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