A satellite orbits the earth at a height of `3.6xx10^(6)m` from its surface. Compute it’s a kinetic energy, b. potential energy, c. total energy. Mass of the satellite `=500kg` mass of the earth `=6xx10^(24)`kg, radius of the earth `=6.4xx10^(6), G=6.67xx10^(-11)Nm^(2)kg^(-2)`.
Text Solution
AI Generated Solution
To solve the problem step by step, we will compute the kinetic energy, potential energy, and total energy of the satellite orbiting the Earth.
### Given Data:
- Height of the satellite above the Earth's surface, \( h = 3.6 \times 10^6 \, \text{m} \)
- Mass of the satellite, \( m = 500 \, \text{kg} \)
- Mass of the Earth, \( M = 6 \times 10^{24} \, \text{kg} \)
- Radius of the Earth, \( R = 6.4 \times 10^6 \, \text{m} \)
- Gravitational constant, \( G = 6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \)
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