Two satellites `A` and `B` of equal mass move in the equatorial plane of the earth, close to earth's surface. Satellite `A` moves in the same direction as the of the rotation of the earth while satellite `B` moves in the opposite direction. Calclate the ratio of the kinetic energy of `B` of that of `A` in the reference frame fixed to the earth `(g=9.8ms^(-2)` and radius of the earth `=6.37xx10^(6)m)`
Text Solution
AI Generated Solution
To solve the problem, we need to find the ratio of the kinetic energies of satellites A and B in the reference frame fixed to the Earth. Here's a step-by-step solution:
### Step 1: Determine the Angular Velocity of the Satellites
The angular velocity (ω) of both satellites can be calculated using the formula for the angular velocity of an object in circular motion:
\[
\omega = \sqrt{\frac{g}{R}}
\]
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