A satellite is revolving in the circular equatorial orbit of radius `R=2xx10^(4)km` from east to west. Calculate the interval after which it will appear at the same equatorial town. Given that the radius of the earth `=6400km` and `g` (acceleration due to gravity) `=10ms^(-2)`
Text Solution
AI Generated Solution
To solve the problem of determining the interval after which a satellite revolving in a circular equatorial orbit will appear at the same equatorial town, we can follow these steps:
### Step 1: Understand the parameters
- **Radius of the satellite's orbit (R)**: \( R = 2 \times 10^4 \) km = \( 2 \times 10^7 \) m (since 1 km = 1000 m)
- **Radius of the Earth (r_E)**: \( r_E = 6400 \) km = \( 6400 \times 10^3 \) m = \( 6.4 \times 10^6 \) m
- **Acceleration due to gravity (g)**: \( g = 10 \, \text{m/s}^2 \)
### Step 2: Calculate the gravitational force
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