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Two heavy particles of masses 40 kg and ...

Two heavy particles of masses 40 kg and 60 kg attracts each other with a fore of `4 xx 10^(-5) N`. If G is `6xx10^(-11) N-m^(2) kg^(-2)`, calculate the distance between them.

Text Solution

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Here `m_(1)=40 kg, m_(2)=60kg `
`F=4mfg=4xx10^(-6)xx10=4xx10^(-5)N`
`G=6xx10^(-11)Nm^(2)kg^(-2),r=?`
Now `F=G(m_(1)m_(2))/(r^(2))impliessqrt((Gm_(1)m_(2))/F)`
`=sqrt((6xx10^(-11)xx40xx60)/(4xx10^(-5)))=0.06m=6cm`
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