The mass and diameter of a planet are twice those of earth. What will be the period of oscillation of a pendulum on this plenet. If it is a 2 second's pendulum on earth?

Explanation

Since `g=GM//R^(2)`. If mass `M` and radius `R` are doubled then `g` will reduce to half. Since time period `t=2pisqrt(l//g)` so `tpropsqrtg`. Therefore time period of a pendulum will be `sqrt(2)` times that on the earth. Thus the time period of seconds pendulum of the earth will be `2sqrt(2)` on the planet.