How far away from the earth does the acceleration due to gravity become `10%` of its value on earth's surface? Radius of earth `= 6.37 xx 10^(6) m`.

How far away from the surface of earth does the acceleration due to gravity become 4% of its value on the surface of earth ? [R_(e )=6400 km]

At what depth below the surface does the acceleration due to gravity becomes 70% of its value in the surface of earth ?

How much below the surface of the earth does the acceleration due to gravity becomes 70% of its value at the surface of earth ? (Take R_(e)=6400 km)

At what height above the earth's surface the acceleration due to gravity will be 1/9 th of its value at the earth’s surface? Radius of earth is 6400 km.

At what depth from earth's surface does the acceleration due to gravity becomes 1/4 times that of its value at surface ?

At which height from the earth's surface does the acceleration due to gravity decrease by 75 % of its value at earth's surface ?

The height of the point vertically above the earth's surface, at which acceleration due to gravtiy becomes 1% of its value at the surface is (Radius of the earth =R)

At what height above the surface of the earth will the acceleration due to gravity be 25% of its value on the surface of the earth ? Assume that the radius of the earth is 6400 km .

The value of acceleration due to gravity will be 1% of its value at the surface of earth at a height of (R_(e )=6400 km)

At what altitude, the acceleration due to gravity reduces to one fourth of its value as that on the surface of the earth ? Take radius of earth as 6.4 xx 10^(6) m , g on the surface of the earth as 9.8 ms^(-2) .