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A projectile is fired vertically from th...

A projectile is fired vertically from the earth's surface with an initial speed of `10 km//s`. Neglecting air drag, how high above the surface of earth will it go?

Text Solution

Verified by Experts

`1/2mv^(2)=0-(GMm)/R=0-(GMm)/(R+h)`
If we put `GM=R^(2)g,` we get
`h=((v^(2))/R)/(2gR-v^(2))=2.5xx10^(4)km`
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