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The escape velocity from the earth is 11...

The escape velocity from the earth is `11.2km//s`. If a body is to be projected in a direcion making an angle `45^(@)` to the vertical, then the escape velocity is

A

`11.2/(sqrt(2))kms^(-1)`

B

`11.2xxsqrt(2)kms^(-1)`

C

`11.2xx2kms^-1`

D

`11.2kms^-1`

Text Solution

Verified by Experts

The correct Answer is:
D
Change in energy `=1/(2(GMm)//R)=1//2Mv_(e)^(2)`
So, it is independent of angle as gravitational field is conservative in nature.
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Knowledge Check

  • The escape velocity from earth is 11.2 km per sec. If a body is to be projected in a direction making an angle 45^(@) to the vertical, then the escape velocity is

    A
    `11.2 xx 2` km/sec
    B
    `11.2` km/sec
    C
    `11.2 xx (1)/(sqrt(2))` km/sec
    D
    `11.2 xx sqrt(2)` km/sec

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    11.2 km/sec
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    1.112 km/sec
    C
    15.8 km/sec
    D
    22.4 km/sec

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