Home
Class 11
PHYSICS
Two bodies with masses M(1) and M(2) are...

Two bodies with masses `M_(1)` and `M_(2)` are initially at rest and a distance `R` apart. Then they move directly towards one another under the influence of their mutual gravitational attraction. What is the ratio of the distances travelled by `M_(1)` to the distance travelled by `M_(2)`?

A

`(M_(1))/(M_(2))`

B

`(M_(2))/(M_(1))`

C

`1`

D

`1/2`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of the distances traveled by two bodies with masses \( M_1 \) and \( M_2 \) as they move towards each other under mutual gravitational attraction, we can follow these steps: ### Step 1: Understand the System We have two masses \( M_1 \) and \( M_2 \) separated by a distance \( R \). Initially, both masses are at rest. As they move towards each other due to gravitational attraction, we need to find the distances they travel until they meet. ### Step 2: Define the Center of Mass The center of mass (CM) of the system can be calculated using the formula: \[ \text{CM} = \frac{M_1 \cdot x_1 + M_2 \cdot x_2}{M_1 + M_2} \] where \( x_1 \) is the distance traveled by \( M_1 \) and \( x_2 \) is the distance traveled by \( M_2 \). ### Step 3: Set Up the Distance Relationship Since both bodies move towards each other and no external forces are acting on them, the center of mass will remain stationary. Thus, the distances traveled by the two masses can be expressed in terms of their masses: \[ M_1 \cdot x_1 = M_2 \cdot x_2 \] ### Step 4: Express Distances in Terms of Total Distance The total distance \( R \) that separates the two bodies is equal to the sum of the distances they travel: \[ x_1 + x_2 = R \] ### Step 5: Solve for the Ratio From the previous equations, we can express \( x_1 \) in terms of \( x_2 \): \[ x_1 = \frac{M_2}{M_1} x_2 \] Substituting this into the total distance equation gives: \[ \frac{M_2}{M_1} x_2 + x_2 = R \] Factoring out \( x_2 \): \[ x_2 \left( \frac{M_2}{M_1} + 1 \right) = R \] Solving for \( x_2 \): \[ x_2 = \frac{R}{\frac{M_2}{M_1} + 1} \] Now substituting \( x_2 \) back to find \( x_1 \): \[ x_1 = \frac{M_2}{M_1} x_2 = \frac{M_2}{M_1} \cdot \frac{R}{\frac{M_2}{M_1} + 1} \] ### Step 6: Find the Ratio Now, we can find the ratio of the distances traveled: \[ \frac{x_1}{x_2} = \frac{\frac{M_2}{M_1} \cdot \frac{R}{\frac{M_2}{M_1} + 1}}{\frac{R}{\frac{M_2}{M_1} + 1}} = \frac{M_2}{M_1} \] Thus, the ratio of the distances traveled by \( M_1 \) to the distance traveled by \( M_2 \) is: \[ \frac{x_1}{x_2} = \frac{M_2}{M_1} \] ### Final Answer The ratio of the distances traveled by \( M_1 \) to the distance traveled by \( M_2 \) is \( \frac{M_2}{M_1} \). ---

To find the ratio of the distances traveled by two bodies with masses \( M_1 \) and \( M_2 \) as they move towards each other under mutual gravitational attraction, we can follow these steps: ### Step 1: Understand the System We have two masses \( M_1 \) and \( M_2 \) separated by a distance \( R \). Initially, both masses are at rest. As they move towards each other due to gravitational attraction, we need to find the distances they travel until they meet. ### Step 2: Define the Center of Mass The center of mass (CM) of the system can be calculated using the formula: \[ ...
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    CENGAGE PHYSICS ENGLISH|Exercise Multiple Correct|24 Videos
  • GRAVITATION

    CENGAGE PHYSICS ENGLISH|Exercise Assertion- Reasoning|13 Videos
  • GRAVITATION

    CENGAGE PHYSICS ENGLISH|Exercise Subjective|15 Videos
  • FLUID MECHANICS

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|1 Videos
  • KINEMATICS-1

    CENGAGE PHYSICS ENGLISH|Exercise Integer|9 Videos

Similar Questions

Explore conceptually related problems

Two particles of masses m and M are initially at rest at an infinite distance apart. They move towards each other and gain speeds due to gravitational attraction. Find their speeds when the separation between the masses becomes equal to d.

Two bodies of mass m_(1) and m_(2) are initially at rest placed infinite distance apart. They are then allowed to move towards each other under mutual gravitational attaction. Show that their relative velocity of approach at separation r betweeen them is v=sqrt(2G(m_(1)+m_(2)))/(r)

Two particles of equal mass (m) each move in a circle of radius (r) under the action of their mutual gravitational attraction find the speed of each particle.

Two bodies of masses M_(1) and M_(2) are kept separeated by a distance d. The potential at the point where the gravitational field produced by them is zero,the gravitational potential will be :-

Two objects of masses m and 4m are at rest at an infinite separation. They move towards each other under mutual gravitational attraction. If G is the universal gravitaitonal constant, then at separation r

10 Two particles of masses m_(1) and m_(2) initially at rest start moving towards each other under their mutual force of attraction. The speed of the centre of mass at any time t, when they are at a distance r apart, is

Two particles of masses m_(1) and m_(2) are intially at rest at an infinite distance apart. If they approach each other under their mutual interaction given by F=-(K)/(r^(2)) . Their speed of approach at the instant when they are at a distance d apart is

Two stationary particles of masses M_(1) and M_(2) are 'd' distance apart. A third particle lying on the line joining the particles, experiences no resultant gravitational force. What is the distance of this particle from M_(1) ?

Two spheres of masses 2 M and M are intially at rest at a distance R apart. Due to mutual force of attraction, they approach each other. When they are at separation R/2, the acceleration of the centre of mass of sphere would be

Two objectes of mass m and 4m are at rest at and infinite seperation. They move towards each other under mutual gravitational attraction. If G is the universal gravitational constant. Then at seperation r

CENGAGE PHYSICS ENGLISH-GRAVITATION-Single Correct
  1. If a man at the equator would weight (3/5)th of his weight, the angula...

    Text Solution

    |

  2. The distance of the centres of moon the earth is D. The mass of earth ...

    Text Solution

    |

  3. Two bodies with masses M(1) and M(2) are initially at rest and a dista...

    Text Solution

    |

  4. If g be the acceleration due to gravity of the earth's surface, the ga...

    Text Solution

    |

  5. A small planet is revolving around a very massive star in a circular o...

    Text Solution

    |

  6. The masses and radii of the Earth and the Moon are M1, R1 and M2,R2 re...

    Text Solution

    |

  7. A spaceship is launched into a circular orbit close to the earth's sur...

    Text Solution

    |

  8. A sky lab of mass 2 xx 10^(3)kg is first launched from the surface of ...

    Text Solution

    |

  9. Consider two satellites A and B of equal mass, moving in the same circ...

    Text Solution

    |

  10. A spherical shell is cut into two pieces along a chord as shown in the...

    Text Solution

    |

  11. Two particles of equal mass go around a circle of radius R under the a...

    Text Solution

    |

  12. A rocket is fired vertically from the surface of the earth with a spe...

    Text Solution

    |

  13. The gravitational potential due to earth at infinite distance from it ...

    Text Solution

    |

  14. A projectile is fired from the surface of earth of radius R with a vel...

    Text Solution

    |

  15. How many hours would make a day if the earth were rotating at such a h...

    Text Solution

    |

  16. Two particles of masses m and Mm are placed a distance d apart. The gr...

    Text Solution

    |

  17. In the solar system, the Sun is in the focus of the system for Sun-ear...

    Text Solution

    |

  18. A body is released from a point of distance R' from the centre of eart...

    Text Solution

    |

  19. A solid sphere of uniform density and radius R applies a gravitational...

    Text Solution

    |

  20. The value of g at a particular point is 10 m s^(-2). Suppose the earth...

    Text Solution

    |