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The gravitational potential due to earth...

The gravitational potential due to earth at infinite distance from it is zero. Let the gravitational potential at a point `P` be `-5 J kg^(-1)`. Suppose, we arbitrarily assume the gravitational potential at infinity to be `+10 J kg^(-1)`, then the gravitational potential at `P` will be

A

`-5Jkg^(-1)`

B

`+5Jkg^(-1)`

C

`-15Jkg^(-1)`

D

`+15Jkg^(-1)`

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The correct Answer is:
To solve the problem, we need to understand how gravitational potential is defined and how it can change based on our reference point. ### Step-by-Step Solution: 1. **Understanding Gravitational Potential**: The gravitational potential \( V \) at a point in a gravitational field is defined as the work done per unit mass to bring a mass from infinity to that point. The potential at infinity is typically taken to be zero. 2. **Given Information**: - The gravitational potential at point \( P \) is given as \( V_P = -5 \, \text{J kg}^{-1} \). - We are considering a new arbitrary reference point where the gravitational potential at infinity is assumed to be \( V_{\infty} = +10 \, \text{J kg}^{-1} \). 3. **Potential Difference Concept**: The gravitational potential difference between two points is what matters in this context. The potential difference between point \( P \) and infinity is given by: \[ \Delta V = V_P - V_{\infty} \] 4. **Calculating the Potential Difference**: Substituting the values we have: \[ \Delta V = V_P - V_{\infty} = -5 - 10 = -15 \, \text{J kg}^{-1} \] 5. **Finding the New Potential at Point \( P \)**: To maintain the same potential difference when we change the reference potential at infinity, we can set up the equation: \[ V_{P'} - V_{\infty}' = -5 \] where \( V_{\infty}' \) is the new potential at infinity (which is \( +10 \, \text{J kg}^{-1} \)). Rearranging gives: \[ V_{P'} = -5 + V_{\infty}' = -5 + 10 = +5 \, \text{J kg}^{-1} \] 6. **Conclusion**: Therefore, the gravitational potential at point \( P \) when the potential at infinity is assumed to be \( +10 \, \text{J kg}^{-1} \) is: \[ V_{P'} = +5 \, \text{J kg}^{-1} \] ### Final Answer: The gravitational potential at point \( P \) is \( +5 \, \text{J kg}^{-1} \). ---

To solve the problem, we need to understand how gravitational potential is defined and how it can change based on our reference point. ### Step-by-Step Solution: 1. **Understanding Gravitational Potential**: The gravitational potential \( V \) at a point in a gravitational field is defined as the work done per unit mass to bring a mass from infinity to that point. The potential at infinity is typically taken to be zero. 2. **Given Information**: ...
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