The electrostatics force of repulsion between two positively charged ions carrying equal charge is `3.7xx10^(-9)N` when these are separated by a distance of `5Å`. How many electrons are missing from each ion?

Explanation

To solve the problem, we will use Coulomb's law and the relationship between charge and the number of missing electrons.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Electrostatic force of repulsion, \( F = 3.7 \times 10^{-9} \, \text{N} \)
- Distance between the ions, \( r = 5 \, \text{Å} = 5 \times 10^{-10} \, \text{m} \)
- Charge of an electron, \( e = 1.6 \times 10^{-19} \, \text{C} \)
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