Two insulated identically sized charged copper spheres A and B have their centers separated by a distance of 50 cm. A third sphere of the same size but uncharged is brought in contact with the first, then in contact with the second and finally removed from both. What is the new force of repulsion between A and B?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the Initial Charges
Let the initial charge on sphere A be \( Q \) and on sphere B also be \( Q \). The distance between the centers of the two spheres is given as \( R = 50 \, \text{cm} \).

### Step 2: Contact with Sphere C
When the uncharged sphere C is brought into contact with sphere A, the charge will redistribute between A and C. Since both spheres are identical in size, they will share the charge equally.

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