Two particles A and B having charges ` 8.0 xx 10 ^(-6) C` and `-2.0 xx 10(-6) C` respectively are held fixed with a. separtion of 20cm. Where should a third charged. particle be placed so that it dose not experience a net electric force?.

Explanation

To solve the problem of where to place a third charged particle so that it does not experience a net electric force due to the two fixed charges A and B, we can follow these steps:

### Step 1: Understand the Configuration
We have two charges:
- Charge A: \( q_A = 8.0 \times 10^{-6} \, C \) (positive charge)
- Charge B: \( q_B = -2.0 \times 10^{-6} \, C \) (negative charge)

They are separated by a distance of \( d = 20 \, cm = 0.2 \, m \).
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