The electric field intensity at the center of a uniformly charged hemispherical shell is `E_(0)`. Now two portions of the hemisphere are cut from either side, and the remaining portion is shown in fig. If `alpha=beta=pi//3`, then the electric field intesity at the center due to the remaining portion is

Options

A. `E_(0)//3`
B. `E_(0)//6`
C. `E_(0)//2`
D. information insufficient

Explanation

The magnitude of electric field intensity due to each part of the hemisherical surface at the center 'O' is same. Suppose it is E.

`E=E/2+E/2=E_(0)`
or, `2E=E_(0)`
or `E=(E_(0))/(2)`.