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Two concentric rings, one of radius a an...

Two concentric rings, one of radius a and the other of radius b, have the charges +q, and `-(2//5)^(-3//2)q`, respectively as shown in fig.

Find the rario `b//a` if a charge particle palaced on the axis at z =a is i equilibrium.

Text Solution

Verified by Experts

The correct Answer is:
2
For the equilbrium of charge at z=a, the net electric field at this point due to both the rings should be zero.
`E_(A)+E_(B)=0implies(kq_(A)a)/((a^(2)+a^(2))^(3//2))+(kq_(B)a)/((b^(2)+a^(2))^(3//2))=0`
Put the value and solve to get `b//a=2`.
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