An uncharged conducting large plate is p...

An uncharged conducting large plate is placed as shown. Now an electric field E towards right is applied. Find the induced charge density on the right surface of the plate.

`-epsilon_0E`

`epsilon_0E`

`-2epsilon_0E`

`2epsilon_0E`

Text Solution

Verified by Experts

The correct Answer is:

b. Net electric field at point P should be zero. For this electric field due to induced charges is equal to the applied electirc field. So,

`sigma/epsilon_0 = E or sigma = epsilon_0E`.

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