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Flux passing through the shaded surface ...

Flux passing through the shaded surface of a sphere when a point charge q is placed at the center is (radius of the sphere is R)

A

`q/epsilon_0`

B

`q/2epsilon_0`

C

`q/4epsilon_0`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
c. `alpha = 60^@`. Solid angle subtended by BCD is
`omega = 2pi (1-cos alpha) = pi`
Solid angle subtended by ABDE is
`omega_(ABCDE) - omega_(BCD) = 2pi - pi = pi`
Hence, flux through ABDE is
`phi = q/epsilon_0 pi/(4pi) = q/(4epsilon_0)`
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