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Gauss's law and Coulomb's law , although...

Gauss's law and Coulomb's law , although expressed in different forms , are equivalent ways of describing the relation between charge and electric field in static conditions . Gauss's law is `epsilon_(0) phi = q_(encl)`,when `q_(encl)` is the net charge inside an imaginary closed surface called Gaussian surface. The two equations hold only when the net charge is in vaccum or air .
The net flux of the electric field through the surface is

A

due to `q_(1)` and `q_(2)` only

B

due to `q_(3)` and `q_(4)` only

C

equal due to all the four charges

D

cannot say

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To find the net electric flux through a closed surface using Gauss's law, we can follow these steps: ### Step 1: Understand Gauss's Law Gauss's law states that the total electric flux (\( \Phi_E \)) through a closed surface is equal to the charge enclosed (\( q_{encl} \)) divided by the permittivity of free space (\( \epsilon_0 \)): \[ \Phi_E = \frac{q_{encl}}{\epsilon_0} \] ### Step 2: Identify the Charges In the given problem, we have four charges: \( Q_1 \), \( Q_2 \), \( Q_3 \), and \( Q_4 \). We need to determine which of these charges are enclosed by the Gaussian surface. ### Step 3: Determine the Enclosed Charge From the information provided: - \( Q_1 \) and \( Q_2 \) are inside the Gaussian surface. - \( Q_3 \) and \( Q_4 \) are outside the Gaussian surface. Thus, the total enclosed charge (\( q_{encl} \)) is: \[ q_{encl} = Q_1 + Q_2 \] ### Step 4: Calculate the Electric Flux Using Gauss's law, we can now calculate the electric flux through the surface: \[ \Phi_E = \frac{Q_1 + Q_2}{\epsilon_0} \] ### Step 5: Conclusion The net electric flux through the closed surface is given by the expression derived above. \[ \Phi_E = \frac{Q_1 + Q_2}{\epsilon_0} \]

To find the net electric flux through a closed surface using Gauss's law, we can follow these steps: ### Step 1: Understand Gauss's Law Gauss's law states that the total electric flux (\( \Phi_E \)) through a closed surface is equal to the charge enclosed (\( q_{encl} \)) divided by the permittivity of free space (\( \epsilon_0 \)): \[ \Phi_E = \frac{q_{encl}}{\epsilon_0} \] ...
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Gauss's law and Coulomb's law , although expressed in different forms , are equivalent ways of describing the relation between charge and electric field in static conditions . Gauss's law is epsilon_(0) phi = q_(encl) ,when q(encl) is the net charge inside an imaginary closed surface called Gaussian surface. The two equations hold only when the net charge is in vaccum or air . A Gaussian surface encloses two of the four positively charged particles. The particles that contribute to the electric field at a point P on the surface are

Gauss's law and Coulomb's law , although expressed in different forms , are equivalent ways of describing the relation between charge and electric field in static conditions . Gauss's law is epsilon_(0) phi = q_(encl) ,when q(encl) is the net charge inside an imaginary closed surface called Gaussian surface. The two equations hold only when the net charge is in vaccum or air . If the charge q_(3) and q_(4) are displaced (always remaining outside the Gaussian surface), then consider the following two statements : A : Electric field at each point on the Gaussian surface will remain same . B : The value of oint vec(E ) .d vec(A) for the Gaussian surface will remain same.

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CENGAGE PHYSICS ENGLISH-ELECTRIC FLUX AND GAUSS LAW-Comprehension
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  11. Positive and negative charges of equal magnitude lie along the symmetr...

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  12. There are two nonconducting spheres having uniform volume charge densi...

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  13. There are two nonconducting spheres having uniform volume charge densi...

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  14. Gauss's law and Coulomb's law , although expressed in different forms ...

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  18. A spherical conductor A contains two spherical cavities as shown in Fi...

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  19. A spherical conductor A contains two spherical cavities as shown in Fi...

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