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1 mu C charge is shifted from A to B, an...

`1 mu C` charge is shifted from A to B, and it is found that work done by an external force is `40 mu J`. In doing so against electrostatic forces, find potential difference `V_A - V_B`.

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We know `W_(ext) = Delta U = q Delta V`
Hence, `(W_(AB))_(ext) = q (V_B - V_A)`
or `40 mu J = 1 mu C (V_B - V_A)`
or `V_A - V_B = -40 V`.
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CENGAGE PHYSICS ENGLISH-ELECTRIC POTENTIAL-DPP 3.5
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