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Figure shows two conducting thin concentric shells of radii `r` and `3 r`. The outer shell carries charge `q` and the inner shell is neutral . The amount of charge that flows from the inner shell to the earth after the key `K` is closed is equal to `(1//n)^(th)` of the charge on the outer shell. What is the value of `n` ?
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Text Solution

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The correct Answer is:
3

Let charge appearing on inner sphere be `x`.
Now potential of inner sphere is zero, i.e.,
`(kq)/(3 r) + (k x)/( r) = 0 or x = -q//3`
Now charge that flows from the inner shell to the earth shall be `-x = q//3`.
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